2x^(2/3)-7x^(1/3)-4=0

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Solution for 2x^(2/3)-7x^(1/3)-4=0 equation: 


x in (-oo:+oo)

2*x^(2/3)-(7*x^(1/3))-4 = 0

2*x^(2/3)-7*x^(1/3)-4 = 0

t_1 = x^(1/3)

2*t_1^2-7*t_1^1-4 = 0

2*t_1^2-7*t_1-4 = 0

DELTA = (-7)^2-(-4*2*4)

DELTA = 81

DELTA > 0

t_1 = (81^(1/2)+7)/(2*2) or t_1 = (7-81^(1/2))/(2*2)

t_1 = 4 or t_1 = -1/2

t_1 = -1/2

x^(1/3)+1/2 = 0

1*x^(1/3) = -1/2 // : 1

x^(1/3) = -1/2

( -1/2 < 0 i 1/3 in (0:1) ) => x należy do O

t_1 = 4

x^(1/3)-4 = 0

1*x^(1/3) = 4 // : 1

x^(1/3) = 4

x^(1/3) = 4 // ^ 3

x = 64

x = 64

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